Simplify
6/sq root 3 +2
My answer is 12 - 6 sq root 3
I am almost sure you meant:
6/(√3 + 2)
then ...
= 6/(√3 + 2) * (√3-2)/(√3-2)
= (6√3 - 12)/(3-4)
= 12 - 6√3 , you are correct
btw, those brackets I put in are essential, or else you would have two terms
If you mean
(6/sqrt(3)) + 2
then, first, multiply the term with the radical (squareroot sign, cuberoot sign, etc.) with radical term, in numerator and denominator:
(6/sqrt(3)) * (sqrt(3)/sqrt(3)) + 2
Then simplify,
(6*sqrt(3) / sqrt(3)^2) + 2
6*sqrt(3) / 3 + 2
2*sqrt(3) + 2
hope this helps~ `u`
Reiny still correct bby
Well, that's a great answer, but let's go on a little adventure and see if we can simplify it just a bit further.
We have 6 divided by the square root of 3 plus 2. To simplify this, we can multiply the top and bottom of the fraction by the conjugate of the denominator, which is also the square root of 3.
So, we get ((6 * square root of 3) + (2 * square root of 3)) / (square root of 3 * square root of 3).
Simplifying further, we have (6 + 2 * square root of 3) / 3, which can be written as (6/3) + (2/3) * square root of 3.
In the end, we get 2 + (2/3) * square root of 3.
So, your answer of 12 - 6 * square root of 3 simplified even further to 2 + (2/3) * square root of 3. Keep up the good work!
To simplify the expression (6/sqrt(3)) + 2, you need to rationalize the denominator.
First, let's rationalize the denominator of the fraction (6/sqrt(3)). To do this, you multiply both the numerator and denominator by the conjugate of the denominator, which is sqrt(3):
(6/sqrt(3)) * (sqrt(3)/sqrt(3))
= (6 * sqrt(3)) / (sqrt(3) * sqrt(3))
= (6 * sqrt(3)) / 3
= 2 * sqrt(3)
Now, the expression becomes:
2 * sqrt(3) + 2
Finally, you cannot combine the term "2 * sqrt(3)" with the constant "2" because they are different types of terms. Thus, the simplified expression is:
2 * sqrt(3) + 2