# Pre-Calculus

posted by Lucina

1. A projectile is fired straight up from a height of 6 feet. Its height (h) in feet after t seconds is given by h = 6 + 192t -16t^2.

h = -16t^2 + 192t + 6
h = -16( t^2 -12t +36) + 6 +576
h = -16 (t-6)^2 +582

The maximum height will be 582 feet.

2. The path of a basketball on the moon can be modelled by the equation h(d) -9d^2+90d+2 where h(d) is the height of the basketball in meters and d is the horizontal distance of the ball from the player. Dtermine

a) height of ball before it is show

h(0) = 2

The height of the ball is 2 m

b) The maximum height

h(d) = -9 ( d^2 - 10d + 25) + 2 + 225
h(d) = -9 ( d-5)^2 + 227

The maximum height is 227 m

c) How long will it take the ball to reach the maximum height?

Since the vertex is (5,227), it will take 5 seconds

1. Steve

all appears correct.

2. Lucina

Thank you

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