Calculate the number of moles required to make 100 mL of a 3.0 M solution of CuSO4·5 H2O.
is the answer .03? if not walk me through the steps thanks
Recall that molarity is moles of solute per liter of solution. It has mol/L (or M) units.
M = n/V
First, we convert the volume (100 mL) to liters units. To convert, we just divide it by 1000:
100 / 1000 = 0.1 L
Since we need to calculate the moles, we rearrange the formula to get n:
n = M*V
Substituting,
n = 3.0 M * 0.1 L
n = 0.3 mol CuSO4·5H2O
hope this helps~ `u`
Well, well, well, looks like we have a mole calculation question here. Let's dive in and find the solution, shall we?
To calculate the number of moles required, we'll use the equation: moles = concentration (M) x volume (L). But before we start crunching numbers, we need to convert the volume to liters.
So, 100 mL is equivalent to 0.1 L. Now, let's plug in the values:
moles = 3.0 M x 0.1 L = 0.3 moles.
Therefore, the number of moles required is indeed 0.3. You were pretty close with your initial answer, just missed a decimal point. No worries, though, you're still a-mole-zing!
Note: 1L = 1000mL, so 100mL = 0.1L
Use proportions:
3 mol are required to make 1 L of 3.0M solution.
x mol are required to make 0.1 L of 3.0M solution.
x=3 mol * 0.1L /(1L)
=0.3 mol
To calculate the number of moles required to make a 3.0 M solution of CuSO4·5 H2O, we need to follow these steps:
Step 1: Determine the molar mass of CuSO4·5 H2O.
The molar mass of CuSO4 is:
(1x63.55 g/mol) + (1x32.07 g/mol) + (4x16.00 g/mol) = 159.61 g/mol.
The molar mass of H2O is:
(2x1.01 g/mol) + (16.00 g/mol) = 18.02 g/mol.
So the molar mass of CuSO4·5 H2O is:
(159.61 g/mol) + (5x18.02 g/mol) = 249.69 g/mol.
Step 2: Calculate the number of moles.
To find the number of moles, we can use the formula:
moles = volume (in liters) x concentration (in Molarity).
First, we need to convert the volume from milliliters to liters:
100 mL = 100/1000 L = 0.1 L.
Now we can calculate the number of moles using the given concentration of 3.0 M:
moles = 0.1 L x 3.0 mol/L = 0.3 moles.
Therefore, the number of moles required to make 100 mL of a 3.0 M solution of CuSO4·5 H2O is 0.3 moles, not 0.03.
To calculate the number of moles required to make 100 mL of a 3.0 M solution of CuSO4·5 H2O, you need to use the formula:
Molarity (M) = moles (n) / Volume (V)
First, let's write down the given information:
Molarity (M) = 3.0 M
Volume (V) = 100 mL (but it's better to convert it to liters)
Step 1: Convert volume to liters:
Since the given volume is in milliliters (mL), you need to convert it to liters by dividing it by 1000:
V = 100 mL / 1000 mL/L = 0.1 L
Step 2: Rearrange the formula to solve for moles (n):
n = M × V
Now, substitute the values into the equation:
n = 3.0 M × 0.1 L = 0.3 moles
Therefore, the number of moles required to make 100 mL of a 3.0 M solution of CuSO4·5 H2O is 0.3 moles, not 0.03.