write as a single logarithm 2IN plus In y munus In2y
ln2 + lny - ln(2y)
ln(2 * y / (2y))
ln(1)
0
If I misread the cryptic 2lN then fix it and follow the rules to get the right answer.
ln(2 * y / (2y))
ln(1)
0
If I misread the cryptic 2lN then fix it and follow the rules to get the right answer.