Write and balance each of the following equations, and then identify each by type.

a) copper+chlorine-->copper(ll)chloride
b) calcium chlorate--->calcium chloride+oxygen
c)lithium+water--->lithium hydroxide+hydrogen
d)lead(ll)carbonate--->lead(ll)oxide+carbon dioxide
I don't know how I would even start this question and I have a test soon. Please help! Thanks in advance.:)

I responded to your question and I asked if you knew the four types of chemical reactions? yes or no. And what do you not understand?

Yes I do know them but I don't get the parts with the parentheses. What do they mean?

copper(II) chloride means it is coper chloride with the copper having a valence of 2. The old names were cuprous chloride for CuCl and cupric chloride for CuCl2. This new way is a way of telling you that it is copper with +2 and not copper with +1.

lead(II) oxide is the same thing. The old names were plumbous oxide for PbO and plumbic oxide for PbO2 (Pb is +4 in it).
For example, a is a way to tell you the equation is
Cu + Cl2 ==> CuCl2

OK thank you! I'm gonna ace this test!:)

Good luck!!

To balance chemical equations, you need to ensure that the number of atoms on both sides of the equation is equal. Here's how you can balance each of the given equations:

a) copper + chlorine → copper(II) chloride

First, count the number of atoms on each side of the equation:
Left Side (Reactants):
- 1 copper (Cu)
- 1 chlorine (Cl)

Right Side (Products):
- 1 copper (Cu)
- 2 chlorine (Cl)

To balance the equation, you need to place a coefficient in front of the compounds or elements until the number of atoms is equal on both sides:

Cu + Cl₂ → CuCl₂

Now, the equation is balanced.

Equation type: Single displacement reaction

b) calcium chlorate → calcium chloride + oxygen

Reactants:
- 1 calcium (Ca)
- 1 chlorate (ClO₃)

Products:
- 1 calcium (Ca)
- 1 chloride (Cl)
- 3 oxygen (O)

To balance the equation, you need to place coefficients:

Ca(ClO₃)₂ → CaCl₂ + 3O₂

Now, the equation is balanced.

Equation type: Decomposition reaction

c) lithium + water → lithium hydroxide + hydrogen

Reactants:
- 1 lithium (Li)
- 1 water (H₂O)

Products:
- 1 lithium (Li)
- 1 hydroxide (OH)
- 1 hydrogen (H)

Let's balance it:

2Li + 2H₂O → 2LiOH + H₂

Now, the equation is balanced.

Equation type: Single displacement reaction

d) lead(II) carbonate → lead(II) oxide + carbon dioxide

Reactants:
- 1 lead (Pb)
- 1 carbonate (CO₃)

Products:
- 1 lead (Pb)
- 1 oxide (O)
- 1 carbon dioxide (CO₂)

To balance the equation:

PbCO₃ → PbO + CO₂

Now, the equation is balanced.

Equation type: Decomposition reaction

Remember, to balance an equation, you need to add coefficients, but do not change the chemical formula of the substances involved.