when an aluminim is immersed in water it displaces 5 kg of water .how is the bouyant force acting on the aluminium object in newtons?(g=10m/s)
buoyant force = weight of water displaced
buoyant force in newton = 5 *10
= 50 newton
To calculate the buoyant force acting on the aluminum object, you can use the formula:
Buoyant force = weight of the displaced water
Since we know that the aluminum object displaces 5 kg of water, we can now calculate the weight of the displaced water.
Weight = mass x gravity
Given:
Mass of the displaced water (m) = 5 kg
Gravity (g) = 10 m/s²
Weight of the displaced water = 5 kg x 10 m/s² = 50 N
Therefore, the buoyant force acting on the aluminum object is 50 Newtons (N).
To calculate the buoyant force acting on the aluminum object, we need to use Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by the object. In this case, the object is displacing 5 kg of water.
First, let's convert the mass of water displaced into its weight. The weight of an object can be calculated using the formula:
Weight = mass × gravity
Given that the mass of water displaced is 5 kg and the acceleration due to gravity is 10 m/s², we find:
Weight of water displaced = 5 kg × 10 m/s² = 50 N
Therefore, the buoyant force acting on the aluminum object is 50 Newtons (N).