math
posted by kudu .
The area of a rhombus is 60cm^2. Given that one of its diagonals is 15 cm long, calculate the perimeter of the rhombus.

area of a rhomus = (1/2)(product of its diagonals)
let the other diagonal be a
(1/2)(15a) = 60
15a= 120
a = 8
So let's find the hypotenuse of one of the rightangled triangles formed by the intersection of its diagonals
base = 4, height = 7.5
if h is the hypotenuse,
h^2 = 4^2 + 7.5^2
h = 8.5
so perimeter = 4(8.5) = 34 cm 
34
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