The area of rectangle is 192 sq. meters its diagonal is 20 in. find its width and length?
xy = 192
x^2+y^2 = 400
Now just find x and y
why it is become equal to 400?
400 is 20^2
looks like you need to review the Pythagorean theorem.
its 400 inches so i have to convert it in meter ryt?
Hmm. yes, good question. However, no rectangle with a diagonal of 20 inches can possibly have an area of 192 square meters!!
I fear you have garbled the question.
To find the width and length of a rectangle, we can use the formula for the area of a rectangle and the Pythagorean theorem.
Let's start with the formula for the area of a rectangle:
Area = length * width
We are given that the area is 192 square meters. Therefore, we have:
192 = length * width ---- (equation 1)
Next, we are given that the diagonal is 20 inches. From the Pythagorean theorem, we know that in a rectangle, the diagonal (d), length (l), and width (w) are related by the equation:
d^2 = l^2 + w^2 ---- (equation 2)
However, since we are given the diagonal in inches and the area in square meters, we need to convert the units.
Converting inches to meters: 1 inch = 0.0254 meters
Therefore, the diagonal in meters (D) is:
D = 20 * 0.0254 ---- (equation 3)
Now, let's substitute equations 1 and 3 into equation 2 to solve for the width and length.
(20 * 0.0254)^2 = (length)^2 + (width)^2
0.4064^2 = (length)^2 + (width)^2
0.16509136 = (length)^2 + (width)^2 ---- (equation 4)
Substituting equation 1 into equation 4, we have:
0.16509136 = (length)^2 + (192/length)^2
We can solve this equation using algebra, or we can use a numerical method to find the values of length and width.
Let's solve this equation using a numerical method.