the half-life of the reaction, at 34 degrees celsius and Ppan=13.2 torr, is 164.0hr. Calculate the rate constant for the reaction.
confused on what to do here
What's Ppan? If this is a first order reaction, you do this.
k = 0.693/t1/2. Solve for k. If this is a second order reaction the above is not the way to go.
ok so 34+273=307
307X1/2=153.5
.693/153.5=.0045
I think its a second order reaction what do I do for that??
To determine the rate constant for a reaction, we can use the half-life equation for a first-order reaction. The equation is as follows:
t1/2 = (0.693 / k)
Where:
- t1/2 is the half-life of the reaction
- k is the rate constant
In this case, we are given the half-life of the reaction (t1/2 = 164.0 hr). We can rearrange the equation to solve for the rate constant (k):
k = 0.693 / t1/2
Substituting the given half-life value into the equation:
k = 0.693 / 164.0 hr
Calculating this expression will give you the rate constant (k) for the reaction at the specified conditions.