physics

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An athlete performing a long jump leaves the ground at a 27.1∘ angle and lands 7.72m away

1.What was the takeoff speed?
2.If this speed were increased by just 5.0%, how much longer would the jump be?

  • physics -

    u = speed * cos 27.1
    7.72 = speed *cos 27.1 * t
    where t is time in air

    h = Hi + Vi t - (1/2) g t^2
    0 = 0 + speed*sin 27.1 * t - 4.9 t^2
    but we know t = 7.72/(speed*cos 27.1)

    call speed s
    0 = 0 + 7.72 tan 27.1 - 4.9*7.72^2/(s^2cos^227.1)
    solve for s

    do it again for s = 1.05 s

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