# chemistry

posted by Anonymous

A solution of HClO is mixed and found to
have a pH of 4.53. Find what the initial
concentration of HClO was for this solution.
Ka = 3.00 × 10−8
for HClO.
Answer in units of mol/L

1. Anonymous

ka= 3.00 * 10 -8

2. DrBob222

pH = 4.53 = -log(H^+). Solve for (H^+) and that's approx 1E-5 but that's just close so you need to do it more accurately.
.........HClO ==> H^+ + ClO^-
I........x........0......0
C.......-y........y.......y
E........x-y......y........y

The problem tells you (actually the (H^+) from above tells you y = 10^-5

Ka = (H^+)(ClO^-)/(HClO)
(H^+) = 1E-5
(ClO^=) = 1E-5
(HClO) = x-1E-5
Solve for x.

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