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Here's my question: Determine if each system has one, two, or no solutions. (Show your work - 3 marks each)

a)y=2x^2-2x+1 and y=3x-5

b)y=x^2+3x-16 and y=-x^2-8x-18

Here's my work on the question:

a)

x=(-b plus/minus sign (square root b^2-4ac)/(2a)
x=(--2 plus/minus sign (square root -2^2-4(2)(1)/(2(2)
x=(2 plus/minus sign (square root -4-8)/(4)
x=( 2 plus/minus sign (non-real answer)/(4)

x=(-b plus/minus sign (square root b^2-4ac)/(2a)
x=(--5 plus/minus sign (square root -5^2-4(3)/2(3)
x=(5 plus/minus sign(square root -25-12)/6
x=(5 plus/minus sign(square root -37)/6
x=(5 plus/minus sign (non-real answer)/6


b)
x=(-b plus/minus sign (square root b^2-4ac)/(2a)
x=(-3 plus/minus sign (square root 3^2-4(1)(-16)/(2(1))
x=(-3 plus/minus sign (square root 9--64)/2
x=(-3 plus/minus sign (square root 73)/2
x=(-3 plus/minus sign (8.54)/(2)
x=4.27

x=(-b plus/minus sign (square root b^2-4ac)/(2a)
x=(--8 plus/minus sign(square root -8^2-4(-1)(-18)/(2(-1)
x=(8 plus/minus sign(square root-64-72)/(-2)
x=(8 plus/minus sign(square root -136)/(-2)
x=(8 plus/minus sign(non-real answer)/(-2)

Can you please help me where I went wrong and help correct my errors!

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