math
posted by samantha .
Every night when Samantha came home from work she put any change she had in her pockets into a jar. One day she wanted to know how much change she had in her jar. She noticed that she had two more nickels than twice the number of dimes, and eight fewer quarters than twice the number of nickels. If the value of the quarters was $1.60 more than four times the value of the nickels and dimes together, what was the total value of the change in Samantha's jar?

plese help

just start writing down the facts as math.
n = 2d+2
eight fewer quarters than twice the number of nickels
q = 2n8
value of the quarters was $1.60 more than four times the value of the nickels and dimes together
25q = 4(10d+5n)+160
Putting all that together, we have
n = 2d+2
q = 2n8
25q = 4(10d+5n)+160
substituting in for q and n in the last equation, we have
25(2(2d+2)8) = 4(10d+5(2d+2))+160
d=15
So, now you know how many dimes there are, and you can figure out the other coins. 
I. Need help in math
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