posted by Jefferson

A strip of zinc medal weighing 2.00 grams is placed in an aqueous solution containing of .750M Tin(II) nitrate. Determine the grams of tin metal that will be precipitated.

  1. Devron

    The reaction is as followed:

    Zn + Sn(NO3)2 --> Sn + Zn(NO3)2

    Convert 0.750M Sn(NO3)2 to moles:

    Molarity (M)= moles/volume (L)

    Molarity*Volume (L)=moles

    moles of Sn(NO3)2=0.750M*0.150L

    This is similar to the limiting reagent problem. Proceed as you would do for the limiting reagent problem.

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