What volume of a 0.50 M MgSO4 solution will be needed to prepare 100.0 mL of a 0.20 M MgSO4 solution?
A.250 mL
B.100 mL
C.0.250 mL
D.40.0 mL
D.40.0 mL
mols MgSO4 neded = M x L = 0.20 M x 0.100 L = 0.02 mols.
Then M MgSO4 = mols MgSO4/L MgSO4.
0.50 = 0.02/L, solve for L.
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To solve this question, we need to use the concept of dilution. Dilution is a process in which a concentrated solution is mixed with a solvent to obtain a less concentrated solution.
The formula to calculate the volume of the concentrated solution needed to prepare a diluted solution is:
C1V1 = C2V2
Where:
C1 = concentration of the concentrated solution
V1 = volume of the concentrated solution
C2 = concentration of the diluted solution
V2 = volume of the diluted solution
In this case, we know:
C1 = 0.50 M
V1 = ?
C2 = 0.20 M
V2 = 100.0 mL
Let's substitute these values into the formula:
(0.50 M) * V1 = (0.20 M) * (100.0 mL)
Now, solve for V1:
V1 = (0.20 M) * (100.0 mL) / (0.50 M)
V1 = 40.0 mL
Therefore, the volume of the 0.50 M MgSO4 solution needed to prepare 100.0 mL of a 0.20 M MgSO4 solution is 40.0 mL.
So, the correct answer is option D. 40.0 mL.