If 14.5g of CO2 gas has a volume of 0.13L at 305K , what is its pressure in millimeters of mercury?
I've plugged these values into the equation P=nRT/V but I am having troubles with canceling labels and getting the correct answer. Please explain as much as possible to me!
Show your work and I'll find the error.
n CO2 = grams/molar mass
P= [14.5g*(0.0821L*atm/mol*K)*305K]/0.13L
P=2792.98
P=2792.98*760mmHg = 2122664.8 g/mol*mmHg
To find the pressure of the CO2 gas in millimeters of mercury (mmHg), you can use the ideal gas law equation:
P = (n * R * T) / V
P = pressure
n = number of moles of CO2 gas
R = ideal gas constant
T = temperature in Kelvin
V = volume
Let's break down the problem step by step:
Step 1: Determine the number of moles of CO2 gas (n)
To calculate the number of moles, you need to use the molar mass of carbon dioxide (CO2), which is the sum of the atomic masses of carbon (C) and oxygen (O).
Molar mass of carbon (C) = 12.01 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Molar mass of CO2 = 12.01 g/mol (C) + 16.00 g/mol (2 oxygens)
= 12.01 g/mol + 32.00 g/mol
= 44.01 g/mol
To find the number of moles, divide the mass of CO2 gas by its molar mass:
n = mass / molar mass = 14.5 g / 44.01 g/mol
Step 2: Convert the temperature to Kelvin (K)
The given temperature is 305K, which is already in Kelvin. No conversion is needed in this step.
Step 3: Convert the volume to liters (L)
Since the given volume is 0.13L, no conversion is necessary in this step.
Step 4: Use the ideal gas law to calculate the pressure (P)
Now that we have obtained the values for n, R, T, and V, we can substitute them into the ideal gas law equation to find the pressure (P).
P = (n * R * T) / V
In this case, R is the ideal gas constant, which is typically given as 0.0821 L•atm/(mol•K).
P = (n * R * T) / V
P = (14.5 g / 44.01 g/mol) * (0.0821 L•atm/(mol•K)) * (305 K) / 0.13 L
To simplify the units, cancel out the appropriate ones:
P = [(14.5 g * 0.0821 L•atm/(mol•K) * 305 K) / (44.01 g/mol * 0.13 L)] * (760 mmHg/1 atm)
By multiplying the numerator and dividing by the denominator, you'll find the pressure in units of mmHg.