A man pulls a wagon with a handle that is at an angle of 42° with the ground. If the man pulls with 330 N of force, how much force pulls the wagon forward?
330 cos 42°
220 N
To find the amount of force that pulls the wagon forward, we need to calculate the component of the force acting in the horizontal direction.
The horizontal component of the force can be calculated using the formula:
Force horizontal = Force × cos(angle)
Given:
Force = 330 N
Angle = 42°
Using the formula:
Force horizontal = 330 N × cos(42°)
Calculating:
Force horizontal = 330 N × 0.7431
Force horizontal ≈ 244.80 N
Therefore, approximately 244.80 N of force pulls the wagon forward.
To determine the amount of force that pulls the wagon forward, we'll need to find the horizontal component of the force exerted by the man.
Given that the man is applying a force of 330 N at an angle of 42° with the ground, we can use trigonometry to find the horizontal component of the force.
The horizontal component can be found using the cosine function, which relates the adjacent side (horizontal component) to the hypotenuse (total force applied by the man).
So, the horizontal component of the force can be calculated as follows:
Horizontal component = Total force × cosine(angle)
= 330 N × cosine(42°)
Calculating this expression will give us the magnitude of the force that pulls the wagon forward.