calculate the molar hydroxide ion concentration of each of the following solutions given the pH 4.53. Answer should be for OH-.
Please show me how to do this in step by step
pOH = 14 - pH
therefore, ur pOH will be = 14 - 4.53
= X (suppose)
pOH = -log[OH^-]
X = -log[OH^-]
Solve for [OH^-]
OH=9.47
-log= 0.976349979
is this correct
okay correct.....so the 9.47 is correct...then you put in your calculator -9.47 2nd log to get 3.388441561 -10, which is rounded off to 3.4 * 10^-10
To calculate the molar hydroxide ion (OH-) concentration from the given pH, you can use the concept of pH and pOH.
Step 1: Determine the pOH value
The pOH is the negative logarithm (base 10) of the hydroxide ion concentration. It is related to pH through the equation: pH + pOH = 14.
In this case, pH is given as 4.53. Therefore, the pOH can be calculated as:
pOH = 14 - pH
pOH = 14 - 4.53
pOH = 9.47
Step 2: Calculate the hydroxide ion concentration
The pOH value can be used to calculate the hydroxide ion concentration. The formula relating pOH to hydroxide ion concentration is: pOH = -log [OH-].
To determine the hydroxide ion concentration, we need to convert the pOH value to OH- concentration by taking the antilog (inverse logarithm) of the pOH. The antilog can be found by using the inverse logarithm function on a calculator.
[OH-] = 10^(-pOH)
In this case:
[OH-] = 10^(-9.47)
Using a calculator, you can evaluate 10^(-9.47) to find the molar hydroxide ion concentration.
So, the step-by-step process to find the molar hydroxide ion concentration given the pH of 4.53 is to first calculate the pOH value and then convert it to the hydroxide ion concentration [OH-] using the formula [OH-] = 10^(-pOH).