calculus
posted by kailey .
Me again. One last question! Again, just needed my answer verified with any explanation or walkthrough.
The position of a particle moving along a coordinate line is s=√(3+6t) with s in meters and t in seconds. find the particle's acceleration at t=1 second.
a. 1 m/sec^2
b. 1/18 m/sec^2
c. 1/3 m/sec^2
d. 1/3 m/sec^2
My answer is D.
thanks ahead of time!!

calculus 
Reiny
s = (3+6t)^(1/2)
v = (1/2)(3+6t)^(1/2) (6) = 3(3+6t)^(1/2)
a = (3/2)(3+6t)^(3/2) (6)
= 9(3+6t)^(3/2)
when t = 1
a =9(9)^(3/2) = 9(1/27) = 1/3
you are correct! 
calculus 
Damon
s = (6t+3)^.5
ds/dt = .5 (6t+3)^.5 (6)
= 3 (6t+3)^.5
d^2s/dt^2 = 3 [ .5(6t+3)^1.5 *6)
= 9 /(6t+3)^1.5
if t = 1
9 / 9^(3/2)
9/27
1/3
yes D 
calculus 
Bosnian
a = ds / dt
a = ( 1 / 2 ) * [ 1 / sqrt ( 6 t + 3 ) ] * 6
a = 3 / sqrt ( 6 t + 3 )
t = 1
a = 3 / sqrt ( 6 * 1 + 3 )
a = 3 / sqrt ( 6 + 3 )
a = 3 / sqrt ( 9 )
a = 3 / 3
a = 1 m / s ^ 2
Answer a. 
calculus 
Bosnian
Sorry.
v = ds / dt
Respond to this Question
Similar Questions

Calculus
A particle is moving along the curve y = 2 √{3 x + 7}. As the particle passes through the point (3, 8), its xcoordinate increases at a rate of 5 units per second. Find the rate of change of the distance from the particle to … 
Calculus
A particle is moving along the curve y = 2 √{3 x + 7}. As the particle passes through the point (3, 8), its xcoordinate increases at a rate of 5 units per second. Find the rate of change of the distance from the particle to … 
Calculus
A particle is moving along the curve y = 2 √{3 x + 7}. As the particle passes through the point (3, 8), its xcoordinate increases at a rate of 4 units per second. Find the rate of change of the distance from the particle to … 
calculus
a particle moves along a number line measured in cm so that its position at time t sec is given by s=72/(t+2) +k, k is a constant and t>=0 seconds. (a) Find the instantaneous velocity of the particle at t=4 seconds (b) Find the … 
math
A particle is traveling along a onedimensional path (such as a number line). The position of the particle is governed by the time function x(t) ƒ 3t 4 ƒ{16t3 ƒy18t 2 ƒy 2 , where t is in minutes and 0 „T t „T 5 . Answer … 
Physics
A particle moved along the x axis with a constant acceleration of 85.0 meters per second squared. The initial position of the particle was at the origin and its initial velocity was +325 meters per second. Find the position of the … 
Calculus
Solve: The posistion of a particle moving along a coordinate line is s=sqrt(5+4t), with s in meters and t in seconds. Find the particle's velocity at t=1 sec. A) 2/3 m/sec B) 4/3 m/sec C) 1/3 m/sec D) 1/6 m/sec Thank you! 
Calculus
The position of a particle moving on a horizontal line is given by s(t)=2t^315t^2+24t5, where s is measured in feet and t in seconds. a: What is the initial position of the particle? 
AP CALC. AB
1.The position of a particle moving on the line y = 2 is given by x(t)= 2t^313t^2+22t5 where t is time in seconds. When is the particle at rest? 
calculus
the position of a particle moving along a coordinate line is s=√(1+4t) , with s in metres and t in seconds. Find the particle's velocity and acceleration at t=6 sec