Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Chemistry
A certain reaction has an equilibrium constant of 0.65. Calculate the constant for the reverse reaction.
1 answer
K fwd = 0.65
K rvse = 1/0.65
You can
ask a new question
or
answer this question
.
Related Questions
I stuck on this problem.
Can you help me to solve it? A reaction mixture in a 3.67L flask at a certain temp. initially contains
1,Given That Ea For The Hydrolysis Of Sucrose Is 108x10^3 KJ/mol,compare The Rate Constant Of Ths Reaction at 37degree C,(T1)
Which statement describes a chemical reaction at equilibrium?
A. The forward reaction happens slightly faster than the reverse
What effect does raising the temperature of the reaction chamber at a constant pressure have on the following reaction at
What information does an equilibrium constant give about a reaction?
A. It tells how long it takes the reaction to reach
Use the data in the table to calculate the equilibrium constant for the following reaction.
HCOOH(aq)+ OH −(aq) equilibrium
The reaction below has an equilibrium constant of
Kp=2.26×104 at 298 K. CO(g)+2H2(g)⇌CH3OH(g) Calculate Kp for the reaction
The following reaction: SO2 (g) <====> SO3 (g) + NO (g) having reached a state of equilibrium, was found to contain 0.40 M SO3,
For the reaction 2NH3(g) 3H2(g) N2(g) at 472oC equilibrium is established when [H2] =0.0200M, [N2] = 0.0100M and [NH3] =
If a catalyst is added to a system at equilibrium and the temperature and pressure remain constant
there will be no effect on