The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. How many grams of sucrose are needed to make 655 mL of a 36.0% (w/v) sucrose solution?
You can do this one of two way.
#1.
(g sucrose/g solution)*100 = 36.0% and solve for g sucrose.
#2. 36.0% means 36 g sucrose/100 g solution.
So how much will it take for 655 mL instead of 100. That will be
36.0g sucrose x (655/100) = ? g sucrose
Check out both and see if you get the same answer.
To find the number of grams of sucrose needed to make a 36.0% (w/v) sucrose solution, we need to multiply the volume of the solution by the percent concentration and convert it to grams.
Step 1: Convert the given 36.0% concentration to a decimal.
36.0% = 36.0/100 = 0.36
Step 2: Calculate the mass of solute needed using the (w/v) abbreviation formula.
m = w/v
mass (in grams) = weight (in grams) / volume (in mL)
Step 3: Plug in the given values into the formula.
mass (in grams) = 0.36 x 655 mL
Step 4: Calculate the mass.
mass (in grams) = 0.36 x 655
mass (in grams) ≈ 235.8 grams
Therefore, approximately 235.8 grams of sucrose are needed to make a 36.0% (w/v) sucrose solution with a volume of 655 mL.
To calculate the number of grams of sucrose needed to make a 36.0% (w/v) sucrose solution, we can use the formula:
Mass of solute (g) = Volume of solution (mL) × Concentration of solute (% w/v)
Let's substitute the given values into the formula:
Volume of solution = 655 mL
Concentration of solute = 36.0% (w/v)
Now we can calculate:
Mass of solute (g) = 655 mL × 36.0%
To find the result, we need to convert the percentage to a decimal by dividing it by 100:
Mass of solute (g) = 655 mL × 0.36
Now we can perform the calculation:
Mass of solute (g) = 235.8 g
So, to make a 655 mL of a 36.0% (w/v) sucrose solution, you would need 235.8 grams of sucrose.