posted by David .
A thermally insulated vessel containing 100 grams of ice at 0 degrees Celsius . Water at 55 degrees celsius is poured and after some time , the system reaches the equilibrium at a temperature of 10 degrees Celsius. That amount of water in grams was placed . ( heat fusion ice 80cal / g . The specific heat capacity of water is about 1cal / ( gr.K )
Here suppose mass of ice formed=m gram
Therefore, mass of water evaporated= 100-m gram
As, no water is left in he vessel ,
Amt. Of heat taken by water in evaporation = amt. Of heat given out by water in freezing