The base of a triangle is terms of x is 2x+4x+2 and the height is x2+3x-4. What is the area of the triangle. I need to know am if I'm on the right track
Area=1/2(2x+4x+2) (x2+3x-4)
Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
Unless you forgot the power on the first x, 2x + 4x = 6x.
Otherwise, you are on the right track.
Trying to find the area of the triangle
Area=1/2(2x^2+4x+2) (x^2+3x-4)
6x^2+2 (x^2+3x-4)
Can someone please help I'm totally lost am I on the right track it's been a while since I took Algebra
Yes, you are on the right track with the formula for calculating the area of a triangle. The area of a triangle is given by the formula:
Area = 1/2 * base * height
So, in your case, the base of the triangle is 2x + 4x + 2, and the height is x^2 + 3x - 4.
To calculate the area, substitute these values into the formula:
Area = 1/2 * (2x + 4x + 2) * (x^2 + 3x - 4)
Simplifying the expression inside the parentheses, we get:
Area = 1/2 * (6x + 2) * (x^2 + 3x - 4)
Multiplying the terms inside the parentheses, we get:
Area = 1/2 * (6x^3 + 18x^2 - 24x + 2x^2 + 6x - 8)
Combining like terms, we get:
Area = 1/2 * (6x^3 + 20x^2 - 18x - 8)
Finally, simplifying further, we get the final expression for the area of the triangle:
Area = 3x^3 + 10x^2 - 9x - 4
Therefore, the area of the triangle in terms of x is 3x^3 + 10x^2 - 9x - 4.