Assuming you are on Earth, where acceleration due to gravity is
9.81 meters/second2, and you have a pendulum with a cord that is 0.65 meters long, what is the period?
To find the period of a pendulum, you can use the formula:
T = 2π * sqrt(L / g)
where:
T is the period (the time it takes for one complete swing),
π is a mathematical constant, approximately equal to 3.14159,
L is the length of the pendulum's cord, and
g is the acceleration due to gravity.
Substituting the given values into the formula, we get:
T = 2π * sqrt(0.65 / 9.81)
Now, let's solve the equation step by step:
1. Divide the length of the cord by the acceleration due to gravity:
L / g = 0.65 / 9.81 ≈ 0.0663
2. Take the square root of the result:
sqrt(0.0663) ≈ 0.2572
3. Multiply the square root by 2π:
2π * 0.2572 ≈ 1.6161
So, the period of the pendulum is approximately 1.6161 seconds.
Where else am i going to be, !@#$%^&?
T^2 = 4*pi^2*(L/g)
T^2 = 39.48(0.65/9.8). Solve for T.