An ideal spring has a spring constant k = 20 N/m. The spring is suspended vertically. A 0.7-kg body is attached to the unstretched spring and released. It then performs oscillations.
To find the period of oscillation for the spring, we can use the formula:
T = 2π√(m/k)
where T is the period, m is the mass attached to the spring, and k is the spring constant.
Given that m = 0.7 kg and k = 20 N/m, we can substitute these values into the formula:
T = 2π√(0.7/20)
T = 2π√(0.035)
T ≈ 2π * 0.187 ≈ 1.177 seconds
Therefore, the period of oscillation for the spring is approximately 1.177 seconds.