What is the slope-intercept form of the equation y – 7 = –5/2 (x + 4)?
y – 2 = –5/2(x + 2)
y + 7 = –x + 5/2
y = –4/7+ 2
y = –5/2x – 3
(I keep coming up with y=5/2(x+4)+7 2. Distribute 5/2 y=(5/2x) + 10 + 7 3. Simplify. y=(5/2)x + 17 and it is not one of the answers. Please help)
1. C
2. A
3. D
4. D
C
A
D
D
A
For geometry
equations of lines in th... is 100% correct btw
its
1-C
2-A
3-D
4-D
y-7 = -5/2 (x+4)
y-7 = -5/2 x - 5/2(4)
y-7 = -5/2 x - 10
y = -5/2 x - 3
^^^ correct
@Anonymous is 100% correct! Thanks bro
omg thanks so much 100 percent right
Thank you!!!!!
To find the slope-intercept form of the given equation, we need to isolate the variable 'y' on one side of the equation and express 'y' in terms of 'x'.
Let's start with the given equation: y – 7 = –5/2 (x + 4)
To isolate 'y', we can start by distributing -5/2 to the terms inside the parentheses:
y - 7 = (-5/2)x - (5/2)(4)
Simplifying the right side of the equation:
y - 7 = (-5/2)x - 20/2
y - 7 = (-5/2)x - 10
Combining like terms on the right side:
y - 7 = (-5/2)x - 10
Next, we can move the constant term (-7) to the other side of the equation by adding 7 to both sides:
y - 7 + 7 = (-5/2)x - 10 + 7
This simplifies to:
y = (-5/2)x - 3
Therefore, the slope-intercept form of the equation y – 7 = –5/2 (x + 4) is y = (-5/2)x - 3.
The options you provided are incorrect because they do not match the simplification steps outlined above.