To make 1.5 L of 0.1 M NaCl from a 2.52 M stock solution, you would need to take
____ mL of the stock solution and add _____ mL of water.
M1V1=M2V2
so
0.1 M x 1.5 L= 2.52 x ?L
?L of 2.52 M stock solution= 0.05 L
To find out how much water you need to add just subtract 1.5 L of original solution from 0.05 L.
so 1.5 L - .05 L = amount of water in L
then just convert you answers to mL.
To calculate the volume of the stock solution and water needed to make 1.5 L of a 0.1 M NaCl solution, we can use the formula:
(M1)(V1) = (M2)(V2)
Where:
M1 is the initial concentration of the stock solution,
V1 is the volume of the stock solution,
M2 is the final concentration of the desired NaCl solution,
and V2 is the final volume of the desired NaCl solution.
Given:
M1 = 2.52 M (concentration of the stock solution)
V2 = 1.5 L (final volume of the desired NaCl solution)
M2 = 0.1 M (final concentration of the desired NaCl solution)
Let's solve for V1, the volume of the stock solution.
(2.52 M)(V1) = (0.1 M)(1.5 L)
To find V1, we rearrange the formula to solve for V1:
V1 = (0.1 M)(1.5 L) / (2.52 M)
V1 ≈ 0.0595 L
To convert the volume from liters to milliliters, we multiply by 1000:
V1 ≈ 59.5 mL
So, you would need to take approximately 59.5 mL of the stock solution.
To find the volume of water needed, subtract the volume of the stock solution from the final volume of the desired NaCl solution:
Volume of water = Final volume - Volume of stock solution
Volume of water = 1.5 L - 0.0595 L
Volume of water ≈ 1.44 L
Since we want the volume of water in milliliters, we multiply by 1000:
Volume of water ≈ 1440 mL
Therefore, to make 1.5 L of a 0.1 M NaCl solution from a 2.52 M stock solution, you would need to take approximately 59.5 mL of the stock solution and add approximately 1440 mL of water.