A bicyclist accelerates –0.87 m/s2 during a 3.8 s interval. What is the change in the velocity of the bicyclist and bicycle?
a = change in velocity / change in time
-.87 = change in velocity / 3.8
so
change in velocity = -3.3 m/s
I dont know the answer
To find the change in velocity, we can use the formula:
Change in velocity (Δv) = Acceleration (a) × Time interval (Δt)
Given:
Acceleration (a) = -0.87 m/s^2
Time interval (Δt) = 3.8 s
Plugging in these values into the formula, we have:
Δv = (-0.87 m/s^2) × (3.8 s)
Δv = -3.306 m/s^2
Therefore, the change in velocity of the bicyclist and bicycle is -3.306 m/s.
To find the change in velocity of the bicyclist and bicycle, we can use the formula:
change in velocity = acceleration × time
Given that the acceleration is -0.87 m/s² and the time interval is 3.8 s, we can now substitute these values into the formula to calculate the change in velocity:
change in velocity = -0.87 m/s² × 3.8 s
change in velocity = -3.306 m/s
Therefore, the change in velocity of the bicyclist and bicycle is -3.306 m/s. Since the velocity is negative, it indicates that the object is decelerating.