chemistry

posted by mathew

10 ml sample of vinegar an aqueous solution 0f acetic acid( HC2H3O2) is titrated with 0.5062 M and 16.58 ml is required to reach equivalence point what is the molarity of the acetic acid

b. if the density of vinegar is 1.006 g/cm3 what is the mass percent of acetic acid of vinegar

  1. DrBob222

    HAc + NaOH ==> NaAc + H2O

    mols NaOH = M x L = estimated 0.008 but you need a more accurate answer for this and all of the other estimates that follow.

    From the equation.
    0.008 mols NaOH = 0.008 mols HAc

    M = mols/L = 0.008/0.010L = about 0.8M

    g HAc = mols x molar mass = approx 0.5g
    mass of 10 mL = 1.006g/mL x 10 mL =?
    mass% = g solute/g solution = about 5%?

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