Pre-Calculus/Trigonometry

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for f(x)= 1/(x^2-3), find:

a. f(3)

b.f(2+h)

  • Pre-Calculus/Trigonometry -

    a.

    Replace x with 3

    f ( 3 )= 1 / ( x ^ 2 - 3 ) =

    1 / ( 3 ^ 2 - 3 ) =

    1 / ( 9 - 3 ) = 1 / 6


    b.

    Replace x with 2 + h

    f ( 2 + h )= 1 / [ ( 2 + h ) ^ 2 - 3 ] =

    1 / ( 2 ^ 2 + 2 * 2 * h + h ^ 2 - 3 ) =

    1 / ( 4 + 4 h + h ^ 2 - 3 ) =

    1 / ( h ^ 2 + 4 h + 1 )

  • Pre-Calculus/Trigonometry -

    oh! thank you, you made it very understanding

  • Pre-Calculus/Trigonometry -

    You're welcome.

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