PreCalculus/Trigonometry
posted by Anonymous
for f(x)= 1/(x^23), find:
a. f(3)
b.f(2+h)

Bosnian
a.
Replace x with 3
f ( 3 )= 1 / ( x ^ 2  3 ) =
1 / ( 3 ^ 2  3 ) =
1 / ( 9  3 ) = 1 / 6
b.
Replace x with 2 + h
f ( 2 + h )= 1 / [ ( 2 + h ) ^ 2  3 ] =
1 / ( 2 ^ 2 + 2 * 2 * h + h ^ 2  3 ) =
1 / ( 4 + 4 h + h ^ 2  3 ) =
1 / ( h ^ 2 + 4 h + 1 ) 
Anonymous
oh! thank you, you made it very understanding

Bosnian
You're welcome.
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