SCIENCE - PLEASE HELP PLESE

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1) Round 578.683 m, 47.3333 kg, and 789.5 cm to four significant figures.
2) Find the weight of a 12.25 kg dog. Round your answer to the correct number of significant figures. Use weight=massxfree-fall acceleration.
3) Round 3155.24m, 8.777 73 cm, and 93.775 57 kg to one less significant figure than they each have currrently.
4) Multiply 4.135 x 4.688 888 887 m x 8.7m round your answer to the correct number of significant figures.

PLEASE explain each of the answers to me in simple language. I need to submit these by tonight and I struggled and I know my answers are wrong. Thank you.

  • SCIENCE - PLEASE HELP PLESE -

    1) Round 578.683 m, 47.3333 kg, and 789.5 cm to four significant figures.

    0,1,2,3,4 round down
    5,6,7,8,9 round up

    578.6 83
    8 is greater than 4
    so this becomes
    578.7 meters

    47.33 33
    3 is less than 4 so this becomes
    47.33 kilograms

    789.5 cm
    This already has four significant figures

  • SCIENCE - PLEASE HELP PLESE -

    2) Find the weight of a 12.25 kg dog. Round your answer to the correct number of significant figures. Use weight=massxfree-fall acceleration.

    g is different in different places on earth. We need it to four significant figures because your mass is to four sig figs.
    I will call 9.806 65 m/s^2 = 9.807 m/s^2

    m g = weight = 12.25 * 9.807 = 120.1 Newtons

  • SCIENCE - PLEASE HELP PLESE -

    3) Round 3155.24m, 8.777 73 cm, and 93.775 57 kg to one less significant figure than they each have currently.
    ====================
    3155.24
    4 is less than 5 so
    3155.3

    3<5 so
    8.7777

    93.77557
    7>5 so
    93.7756

  • SCIENCE - PLEASE HELP PLESE -

    4) Multiply 4.135 x 4.688 888 887 m x 8.7m round your answer to the correct number of significant figures.
    ============================
    You only have 2 sig figs because you said
    8.7 not 8.70000000
    so
    19.388555555
    is
    19 <-------answer

  • SCIENCE - PLEASE HELP PLESE -

    Thank you Damon

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