what is the system of equation of:
0.25x+0.15y=2.5
1.25x-1.25y=7.5
Multiply Eq1 by 1.25 and Eq2 by 0.25 and subtract:
0.3125x + 0.1875y = 3.125
0.3125x - 0.3125y = 1.875
Diff. : 0.5Y = 1.25
Y = 2.5
In Eq1, replace y with 2.5:
0.25x + 0.15*2.5 = 2.5
0.25x = 2.5 - 0.375 = 2.125
X = 8.5
To find the system of equations, we need to rewrite both equations in standard form, where the variables are on one side of the equation and the constants on the other side.
Let's start with the first equation:
0.25x + 0.15y = 2.5
To eliminate decimals, we can multiply the entire equation by 100:
100 * (0.25x + 0.15y) = 100 * 2.5
25x + 15y = 250
Now let's move on to the second equation:
1.25x - 1.25y = 7.5
Again, to eliminate decimals, we multiply the equation by 100:
100 * (1.25x - 1.25y) = 100 * 7.5
125x - 125y = 750
So, the system of equations in standard form is:
25x + 15y = 250
125x - 125y = 750