Math
posted by Pao
With s(t) measured in feet and t in seconds, the equation s(t)= 16t^2 + 32t expresses the height of a ball above the ground after t seconds if it were thrown upward with a velocity of 32 ft/sec.
(a) What is the maximum height of the ball?
(b) After how many seconds will the maximum height occur?
Respond to this Question
Similar Questions

Algebra
THe function h(t)=16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time … 
Algebra
THe function h(t)=16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time … 
Algebra
If a ball is thrown vertically upward from a height of 56ft. above ground with an initial velocity of 40ft. per second, then the height of the ball above ground t seconds after it is thrown is given by f(t)=16t^2 + 40t +56. How many … 
Math
The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 80 feet per second is f (t) = 16t^2 + 80t + 6. According to Rolle's Theorem, what must be the velocity at some time in … 
Calculus Help
If a ball is thrown vertically upward from the roof of 64 foot building with a velocity of 32 ft/sec, its height after t seconds is s(t)=64+32tâ€“16t2. What is the maximum height the ball reaches "in ft"? 
Math
A model airplane is shot up from a platform 1 foot above the ground with an initial upward velocity of 56 feet per second. The height of the airplane above ground after t seconds is given by the equation h=16t^+56t+1, where h is the … 
Algebra 1
a ball is thrown into the air with an upward velocity of 32 ft per second. Its height h in feet after t seconds is given by the function h(t)=16t^2 +32t+6. How long does it take the ball to reach its maximum height? 
Math
A ball is thrown into the air with an upward velocity of 48ft/s. It's height h in feet after t seconds is given by the function h=16t^+48t+8. In how many seconds will the ball hit the ground? 
Algebra
The equation h = 16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach its maximum height? 
Algebra
The equation h= 16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground,at t seconds after the ball is thrown upward.How many seconds after the ball is thrown will it reach its maximum height?