2m+3/m=1
2 m^2 + 3 = m
2 m^2 - m + 3 = 0
m = [ 1 +/- sqrt (1 - 24) ]/ 4
= [ 1 +/- sqrt(-23) ]/4
complex conjugate pair.
Ohk
To solve the equation 2m + 3/m = 1, we can follow these steps:
Step 1: Multiply both sides of the equation by the denominator "m" to eliminate the fraction:
(2m) * m + (3/m) * m = 1 * m
2m^2 + 3 = m
Step 2: Rearrange the equation in the standard quadratic form (ax^2 + bx + c = 0):
2m^2 - m + 3 = 0
Step 3: To solve this quadratic equation, we can use the quadratic formula:
m = (-b ± √(b^2 - 4ac)) / (2a)
In our equation, a = 2, b = -1, and c = 3. Substituting these values into the quadratic formula, we have:
m = (-(-1) ± √((-1)^2 - 4 * 2 * 3)) / (2 * 2)
Simplifying further:
m = (1 ± √(1 - 24)) / 4
m = (1 ± √(-23)) / 4
Step 4: Since the square root of a negative number gives an imaginary solution, there are no real solutions for this equation. Therefore, the equation 2m + 3/m = 1 has no solution.