Math

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Decide whether each equation has one solution, no solutions, or infinitely many solutions. 3(y-3)=2y-9+y
A. One solution
B. No Solutions
C. Infinitely many solutions
I did 3*y
3*3=9
2y=9+4
3-*=-6
x-27
Is the answer A?

  • Math -

    3(y-3)=2y-9+y

    Distribute the 3

    3y-9=2y-9+y

    Combine the like terms that are on the right side "2y" and "y"

    3y-9=3y-9

    You can stop right here because the equations are the same on both sides. This tells you that no matter what y is it will be equal on both sides. Which is why the answer is C.

    Did I explain clearly?

  • Math -

    3(y - 3) = 2y - 9 + y (Distribute on left side, and combine 2y and y on right side.)
    3y - 9 = 3y - 9 (Subtract 3y on both sides.)
    3y 3y - 3y - 9 = - 9 (Add 9 to both sides.)
    3y - 3y = -9 + 9
    0 = 0 (Final result.0

    So the answer is C because x could be any number and you'll still get 0 as the final result of the equation.

    I hope this helps! :)

  • Math (Error) -

    ___3(y - 3) = 2y - 9 + y (Distribute on left side, and combine 2y and y on right side.)
    _____3y - 9 = 3y - 9 - 3y(Subtract 3y on both sides.I meant to put - 3y in the right spot in my first post to help you Gwen.)
    3y - 3y - 9 = - 9 (Add 9 to both sides.)
    ____3y - 3y = -9 + 9
    __________0 = 0 (Final result.)

    So the answer is C because x could be any number and you'll still get 0 as the final result of the equation.

    I hope this helps! :)

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