Math
posted by Gwen
Decide whether each equation has one solution, no solutions, or infinitely many solutions. 3(y3)=2y9+y
A. One solution
B. No Solutions
C. Infinitely many solutions
I did 3*y
3*3=9
2y=9+4
3*=6
x27
Is the answer A?

Mia
3(y3)=2y9+y
Distribute the 3
3y9=2y9+y
Combine the like terms that are on the right side "2y" and "y"
3y9=3y9
You can stop right here because the equations are the same on both sides. This tells you that no matter what y is it will be equal on both sides. Which is why the answer is C.
Did I explain clearly? 
Brady
3(y  3) = 2y  9 + y (Distribute on left side, and combine 2y and y on right side.)
3y  9 = 3y  9 (Subtract 3y on both sides.)
3y 3y  3y  9 =  9 (Add 9 to both sides.)
3y  3y = 9 + 9
0 = 0 (Final result.0
So the answer is C because x could be any number and you'll still get 0 as the final result of the equation.
I hope this helps! :) 
Brady
___3(y  3) = 2y  9 + y (Distribute on left side, and combine 2y and y on right side.)
_____3y  9 = 3y  9  3y(Subtract 3y on both sides.I meant to put  3y in the right spot in my first post to help you Gwen.)
3y  3y  9 =  9 (Add 9 to both sides.)
____3y  3y = 9 + 9
__________0 = 0 (Final result.)
So the answer is C because x could be any number and you'll still get 0 as the final result of the equation.
I hope this helps! :)
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