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The least common multiple of two numbers is 60 and one of the other number is 7 less than the other number what are the numbers justify your answer

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Let numbers be x and y where y is greater y-x=7-equ(1) 60/x-60/y=7-equ(2) simplify equ 2:60y-60x/xy=7 60(y-x)/xy=7-equ 3 subt equ1 in equ3:420=7xy 420=7x(7+x) divide both sds by 7:60=x(7+x) x^2+7x-60=0 x(x+12)-5(x+12)=0 x=+5 y=7+5=12

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I don't now.

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