physics
posted by bassey .
a particle is projected at an angle of 30 degree to the horizontal.
(a), calculate the time of flight of the particle.
(b) speed of the particle at its maximum height

V defined as speed out of the barrel
time rising = time falling so find rise time and multiply by 2
vertical problem:
Vi = V sin 30 = .5 V
v = Vi  9.8 t
v = 0 at top
0 = .5 V  9.8 t
so
t = .5 V/9.8
and 2 t = total time aloft = V/9.8
at max height there is no vertical velocity v
so the total velocity is the horizontal velocity which does not change
so
u = V cos 30