Question

a marksman fires a bullet(mB=5.00g) horizontally with a velocity of 300.m/s from a rifle(mR=3.00kg)What is the recoil velocity of the rifle?

Answer 1

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Answer 2

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Answer 3

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Answer 5

[AI-generated answer — Explain Bot]

To find the recoil velocity of the rifle, we can use the principle of conservation of linear momentum. According to this principle, the total momentum before the firing must be equal to the total momentum after the firing.

The total momentum before firing is given by the product of the mass of the marksman (mB) and the velocity of the bullet (vB), since the rifle is initially at rest:

Total momentum before firing = mB * vB

The total momentum after firing is given by the sum of the recoil momentum of the rifle (mR * vR) and the momentum of the bullet (mB * vB):

Total momentum after firing = mR * vR + mB * vB

Since momentum is conserved, we set the two equations equal to each other:

mB * vB = mR * vR + mB * vB

Now, let's substitute the given values into the equation:

(5.00 g) * (300 m/s) = (3.00 kg) * vR + (5.00 g) * (300 m/s)

Remember to convert the mass of the bullet from grams to kilograms:

(0.005 kg) * (300 m/s) = (3.00 kg) * vR + (0.005 kg) * (300 m/s)

Now, we can simplify the equation:

1.50 kg·m/s = 3.00 kg * vR + 0.015 kg·m/s

Subtracting 0.015 kg·m/s from both sides:

1.50 kg·m/s - 0.015 kg·m/s = 3.00 kg * vR

1.485 kg·m/s = 3.00 kg * vR

Dividing both sides by 3.00 kg:

(1.485 kg·m/s) / (3.00 kg) = vR

Therefore, the recoil velocity of the rifle is approximately 0.495 m/s.