posted by Aly .
What is the domain of the following function?
f(x) = √ -x + 2 - 1
You will have to use brackets to show where the square root ends
I suspect it is f(x) = √(-x+2) - 1 , or else why not combine the +2-1 ?
then the number under the square root must not be negative, that is ...
-x + 2 ≥ 0
-x ≥ -2
x ≤ 2
depends. How much of all that is under the radical sign?
Once you specify that, just remember that the domain of √u is u>=0.