Maths (differentiation)
posted by Francis .
Differentiate
Y = 1/SinX^2

the way you typed it, Wolfram read it as
http://www.wolframalpha.com/input/?i=+Y+%3D+1%2FSinX%5E2
and y = (sinx)^2
dy/dx = 2(sinx)^3 (cosx)
= 2cotx /sin^2 x
or
= 2cotx csc^2 x
if you meant:
y = 1/ sin(x^2)
then y = sin(x^2)^1
dy/dx = 1sin(x^2)^2 cos(x^2) (2x)
= 2x cot(x^2) csx(x^2)
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