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With brakes fully applied, a 1370 kg car deccelerates from a speed of 98.0 km/hr. What is the work done by the braking force in bringing the car to a stop?

  • physics -

    Initial speed = 98 km/h = 98/3.6 m/s

    Work done
    = KE(final)-KE(initial)
    = (1/2)1370(0²-(98/3.6)²)
    = -508 kJ (approx.)

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