physics
posted by charles .
With brakes fully applied, a 1370 kg car deccelerates from a speed of 98.0 km/hr. What is the work done by the braking force in bringing the car to a stop?

Initial speed = 98 km/h = 98/3.6 m/s
Work done
= KE(final)KE(initial)
= (1/2)1370(0²(98/3.6)²)
= 508 kJ (approx.)
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