calculate the volume of o2 and volume al needs photon combison on 18 kg at carbon
See your other post above.
To calculate the volume of O2 and the volume of Al needed for the photon combination with 18 kg of carbon, we need to consider the balanced chemical equation and use the concept of stoichiometry.
1. Start by writing the balanced chemical equation for the reaction between carbon (C), oxygen (O2), and aluminum (Al):
C + O2 → CO2 ... (1)
4Al + 3O2 → 2Al2O3 ... (2)
2. Determine the molar mass of carbon (C), oxygen (O2), and aluminum (Al).
- Molar mass of C = 12.01 g/mol
- Molar mass of O2 = 2 * 16.00 g/mol = 32.00 g/mol
- Molar mass of Al = 26.98 g/mol
3. Convert the given mass of carbon (18 kg) to grams:
Mass of C = 18 kg * 1000 g/kg = 18000 g
4. Calculate the moles of carbon (C) using its molar mass:
Moles of C = Mass of C / Molar mass of C
= 18000 g / 12.01 g/mol
5. According to the balanced equation (1), the ratio of moles of C to moles of O2 is 1:1.
Therefore, the moles of O2 required will be equal to the moles of C.
6. Convert the moles of O2 to volume using the ideal gas law:
PV = nRT
V = nRT / P
Since n (moles) and R (ideal gas constant) are constant, we assume constant temperature and pressure for simplicity.
7. Calculate the volume of O2:
V(O2) = Moles of O2 * R * T / P
8. Similarly, calculate the volume of Al using the balanced equation (2).
According to the equation, 3 moles of O2 are required for every 4 moles of Al.
So, the ratio of moles of C to moles of Al is 4:3.
9. Calculate the moles of Al:
Moles of Al = (Moles of C) * (3 moles of Al / 4 moles of C)
10. Convert the moles of Al to volume using the ideal gas law:
V(Al) = Moles of Al * R * T / P
Note: The specific values used for temperature and pressure should be provided to get the accurate volume.
By following these steps and plugging in the appropriate values, you can calculate the volumes of O2 and Al needed for the photon combination with 18 kg of carbon.