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A lab assistant wants to make 5 liters of 27.2% acid solution. If solutions of 30% and 16% are in stock, how many liters of each must be mixed to prepare the solution?

  • algebra -

    amount of the 30% solution needed ---- x L
    amount of the 16% solution needed --- 5-x L

    .3x + .16(5-x) = .272(5)
    times 100
    30x + 16(5-x) = 136
    30x +80 - 16x = 136
    14x = 56
    x = 4 L

    4 L of the 30%, and 1 L of the 16% solution would be needed.

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