algebra
posted by annie .
A lab assistant wants to make 5 liters of 27.2% acid solution. If solutions of 30% and 16% are in stock, how many liters of each must be mixed to prepare the solution?

algebra 
Reiny
amount of the 30% solution needed  x L
amount of the 16% solution needed  5x L
.3x + .16(5x) = .272(5)
times 100
30x + 16(5x) = 136
30x +80  16x = 136
14x = 56
x = 4 L
4 L of the 30%, and 1 L of the 16% solution would be needed.
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