posted by jeremy .
calculate the Ph of a solution composed of 0.75 grams of KOH dissolved in 500ml of water. assume total ionization.
KOH ==> K^+ + OH^-
mols KOH = grams/molar mass = ?
M KOH = mols KOH/L solution = ?
pOH = -log(KOH)
Then pH + pOH = pKw = 14. You know pKw and pOH, calculate pH.