if a solution is made by adding 83 grams.of soduim hydroxide to 750 ml.of water what is the percent by mass of sodium hydroxide in the solution?
9.96% is the correct answer, trust me! :p
To find the percent by mass of sodium hydroxide in the solution, we need to calculate the mass of sodium hydroxide and the total mass of the solution.
Given information:
Mass of sodium hydroxide = 83 grams
Volume of water = 750 ml
First, we convert the volume of water from milliliters (ml) to grams (g) since the mass and volume need to be in the same unit for calculation.
1 ml of water = 1 gram
So, the mass of water = 750 grams
The total mass of the solution = mass of sodium hydroxide + mass of water
= 83 grams + 750 grams
= 833 grams
Now, we can calculate the percent by mass of sodium hydroxide using the formula:
Percent by mass = (mass of sodium hydroxide / total mass of solution) * 100%
Percent by mass = (83 grams / 833 grams) * 100%
= 9.96%
Therefore, the percent by mass of sodium hydroxide in the solution is approximately 9.96%.
To find the percent by mass of sodium hydroxide in the solution, you need to calculate the mass of sodium hydroxide and then divide it by the total mass of the solution.
First, convert the volume of water from milliliters (ml) to grams (g), assuming water density of 1 g/ml:
750 ml × 1 g/ml = 750 g
Next, you need to find the mass of sodium hydroxide added to the solution, which is given as 83 grams.
Now, calculate the total mass of the solution by adding the mass of sodium hydroxide to the mass of water:
Total mass of solution = Mass of sodium hydroxide + Mass of water
Total mass of solution = 83 g + 750 g = 833 g
Finally, calculate the percent by mass of sodium hydroxide in the solution using the following formula:
Percent by mass = (Mass of sodium hydroxide / Total mass of solution) × 100
Plugging in the values, we have:
Percent by mass = (83 g / 833 g) × 100
Percent by mass ≈ 9.97%
Therefore, the percent by mass of sodium hydroxide in the solution is approximately 9.97%.