Algebra

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multiply (n^3+8)(n-4) can you give me an example on how to solve this please

  • Algebra -

    do things just as you would with numbers:

    (2+5)(7-3)
    2*7 + 5*7 - 2*3 - 5*3

    You have

    (n^3+8)(n-4)
    n^3*n + 8*n - n^3*4 - 8*4
    now simplify each term
    n^4 + 8n - 4n^3 - 32
    and arrange in descending powers
    n^4 - 4n^3 + 8n - 32

    Sometimes you may have several terms with the same power. In that case, collect them into a single term. For example,

    n^3 - 2n^2 + 3 + 9n^2 - 2n + 3 - 4n
    would become simply
    n^3 + 7n^2 - 6n + 6

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