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A 5kg crate falls from height of 2 m into an industrial spring scale. When the crate comes to rest the compression of the spring is 25 cm what is the spring constant?

  • physics -

    loss of gravitational potential energy
    = m g * change in height
    = 5 * 9.81 *(2 + .25)
    = 110 Joules
    that is now stored in the spring (1/2)kx^2
    so
    (1/2) k (.25)^2 = 110

    k = 3532 N/m

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