Post a New Question

physics

posted by .

A 5kg crate falls from height of 2 m into an industrial spring scale. When the crate comes to rest the compression of the spring is 25 cm what is the spring constant?

  • physics -

    loss of gravitational potential energy
    = m g * change in height
    = 5 * 9.81 *(2 + .25)
    = 110 Joules
    that is now stored in the spring (1/2)kx^2
    so
    (1/2) k (.25)^2 = 110

    k = 3532 N/m

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question