There are 18 animals in the farm. Some are chickens and some are cows. I counted 50 legs in all. How many of the animals are cows and how many are chickens?
k+c=18
2k+4c=50
Can someone help me to finish the problem? Thanks.
k+c=18
2k+4c=50
k = 18 - c
2(18 - c) + 4c = 50
36 - 2c + 4c = 50
2c = 14
c = 7
You just have to make a system of equations and use it to find the solution:
x+y=18 -4x-4y=-72 y=-22/-2 y=11 x+11=18 x=7
4x+2y=50 +4x+2y=50
-2y=-22
I hope it will help :)
To solve the system of equations, we can use the method of substitution.
From the first equation, k + c = 18, we can isolate one variable in terms of the other. Let's isolate k:
k = 18 - c
Now substitute this expression for k in the second equation:
2(18 - c) + 4c = 50
Expand the equation:
36 - 2c + 4c = 50
Combine like terms:
2c = 50 - 36
2c = 14
Divide both sides by 2:
c = 7
Now we have the number of cows. Substitute this value back into the first equation to find the number of chickens:
k + 7 = 18
Subtract 7 from both sides:
k = 18 - 7
k = 11
Therefore, there are 11 chickens and 7 cows on the farm.
Sure, let's solve the problem!
To solve this problem, we can use a system of equations. The first equation will represent the total number of animals, and the second equation will represent the total number of legs.
Let's start by assigning some variables:
Let's say k represents the number of chickens.
And let's say c represents the number of cows.
According to the information given, we know that the number of chickens plus the number of cows equals 18, so our first equation is:
k + c = 18
Next, we know that chickens have 2 legs and cows have 4 legs. Since the total number of legs is 50, we can create our second equation:
2k + 4c = 50
Now, we have a system of equations:
k + c = 18
2k + 4c = 50
To solve this system of equations, we can use a method called substitution or elimination.
One approach we can take is to solve the first equation for k and substitute it into the second equation.
From our first equation, we have k = 18 - c.
Substituting this into the second equation, we get: 2(18 - c) + 4c = 50
Now we can simplify and solve for c:
36 - 2c + 4c = 50
2c = 50 - 36
2c = 14
c = 7
So, we have found that there are 7 cows on the farm.
To find the number of chickens, we can substitute the value of c back into one of the original equations. Let's use the first equation:
k + 7 = 18
k = 18 - 7
k = 11
So, we have found that there are 11 chickens on the farm.
To summarize:
There are 7 cows and 11 chickens on the farm.