posted by Victoria
At how many points does the graph of y = (x-6)^2 intersect the x-axis?
If x = 6, bang
if x = 6 bang
so at ONE point
x = 6 which is the vertex of the parabola. It just grazes the x axis and both roots are right there.
I'm sorry but I'm slightly confused. How does x = 6 when the graph is y =(x-6)^2?
When x = 6
(x-6) = 0
y = 0 when x = 6
That is when it hits the x axis