chemistry
posted by susan .
Calculate the [H+] for a solution with [OH−] = −80 M.
1x10*14/80=log(answer)
How would I do this since I can not take the negative log of the previous anwser

I can tell you how to do it if you can tell me how you get a concn of anything less than zero. I can see (OH^) = 1 x 10^80 but that is still more than zero. Not by much I'll grant you, but still more than zero.
Respond to this Question
Similar Questions

chemistry
Please, can someone help? Evaluate log 1. This is my work up until I have gotten stuck: log 1 1=10^x I can't find a common base for 1 and 10^x. Wow, my apologies, this is algebra, not chemistry. but actually I think they use it in 
math
solve for x without using a calculator 5^(x+1) = 25 i know that x would equal 1 because 5^2 is 25, but i don't know how to show how to solve it All you need to do is what you just did: Explain that if x = 1, the equation is satisfied. … 
Math Help Please
Which of the following expressions is equal to log (x sqrty)/z^5 A. log x + log (1/2) + log y– log 5 – log z B. log [x + (1/2)y – 5z] C. log x + (1/2)log y – 5 log z d. [(1/2) log x log y]/(5 log z) 
math
Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25) … 
Math
Are all statements that are true. (a) log(A)/log(B)=In(A)/In(B) (b) In log[b](N), the exponent is N. (c)If 2log[3](81)=8, then log[3](6.561)=8 (d)log[b](N) negative when N is negative. (e)In(x/2)=In(x)/2 
Math
Are all statements that are true. (a) log(A)/log(B)=In(A)/In(B) (b) In log[b](N), the exponent is N. (c)If 2log[3](81)=8, then log[3](6.561)=8 (d)log[b](N) negative when N is negative. (e)In(x/2)=In(x)/2 
biology
Given the part of the molecule shown below, can the underlined atom participate in a hydrogen bond with an approriate bonding partner? 
Math
Find the exact solution, using common logarithms, and a twodecimalplace approximation of each solution. log(7x + 4) = 2 + log(2x − 3) Solve the equation. log(x^3) = (log x)^2 
stats
The following data were collected from a casecontrol study of breast cancer and fat intake: case control Highfat diet 10 5 Lowfat diet 40 55 50 60 Statistical inferences for odds ratios are based on the natural log of the odds ratio, … 
College Algebra
Use the Laws of Logarithms to combine the expression. 1/5log(x + 3)^5 +1/3 [log x^6 − log(x^2 − x − 12)^3]